Coaches' Votes Round 11

[MCG-Unit]

G Goast vs Saints

10 Riewoldt (St K)

5 Armitage (St K)

4 Steven (St K)

3 Blake (St K)

3 Dal Santo (St K)

3 Gram (St K)

2 Goddard (St K)

[Life Long Saint]

Fairly reflective of the game...Other than Roo it was hard to find stand out performances.

If my logic is correct then only three players (Roo, Armo and one of Blake, Dal and Gram) got votes from both coaches.

[perfectionist]

...If my logic is correct then only three players (Roo, Armo and one of Blake, Dal and Gram) got votes from both coaches.

And one of the ones who didn't was Jack Steven, who got four votes from one coach and none from the other.

[elizabethr]

...If my logic is correct then only three players (Roo, Armo and one of Blake, Dal and Gram) got votes from both coaches.

And one of the ones who didn't was Jack Steven, who got four votes from one coach and none from the other.

How do you work that out please?

[jays]

not to bad

[saintbrat]

...If my logic is correct then only three players (Roo, Armo and one of Blake, Dal and Gram) got votes from both coaches.

And one of the ones who didn't was Jack Steven, who got four votes from one coach and none from the other.

How do you work that out please?

Possible combinations given the votes given are 5,4 ,3,2,1

10 Riewoldt (St K)-- Must be 5 + 5

5 Armitage (St K)- either 4 + 1 or 2 + 2---

4 Steven (St K)- 4 or 2 + 2

3 Blake (St K) - 3 alone or 2 + 1

3 Dal Santo (St K)- 3 alone or 2 + 1

3 Gram (St K)- 3 alone or 2 + 1

2 Goddard (St K)- 2 alone or 1 + 1

so eliminating obvious voting excess of 2's would suggest Armo got 4+ 1
so leaves 2 X 2 and 1 'X 1
as the 3's require the 2's to make sense then Jack must have the 4 alone

meaning 2X5 is gone 2 x 4 is gone , 1X 1 is gone
so 1 X 1 left meaning 2 of the 3's are available

hence 1 of Dal Gram and Blake is 2 + 1 and the others are 3 alone

with BJ getting the 2

[SainterK]

Is Armo tracking to finish top 5 of the B&F this year?

[perfectionist]

...If my logic is correct then only three players (Roo, Armo and one of Blake, Dal and Gram) got votes from both coaches.

And one of the ones who didn't was Jack Steven, who got four votes from one coach and none from the other.

How do you work that out please?

Nick got ten, so he must have scored five from both coaches.
David got five, so he must have got 4 from one coach and one from the other.
That leaves a four vote from the other coach, which must have gone to Jack (none of the others have four votes to allocate). Therefore, he did not score a vote from the other coach.

[Life Long Saint]

...If my logic is correct then only three players (Roo, Armo and one of Blake, Dal and Gram) got votes from both coaches.

And one of the ones who didn't was Jack Steven, who got four votes from one coach and none from the other.

How do you work that out please?

Well...Let's start with the easy parts...
10 votes to Roo...That means that each coach gave him the full 5 votes each.
That means that for Armo to get five votes he needs the two coaches to give him (4-1 or 2-3) because the 5 votes is not available...We'll keep this one aside for a minute.
Now it gets trickier...
Let's go to Goddard on two votes...This can come via a 2-0 or 1-1 split. Given that three players are on three votes the 1-1 option is gone as three players got three votes which means that one coach had to give Blake, Dal Santo or Gram one vote. This also takes the 2-3 option away for Armo.

So we are left with.
Roo 5-5
Armo 4-1
BJ 2-0
Dal Santo, Blake and Gram have 3-0, 0-3 and 1-2 (we can't tell which player gets which combination)

This also takes the 2-2 and 3-1 option away for Steven leaving 4-0.

Hope that helps...

[Quixote]

[elizabethr]

Thanks for the explanations.

[saintbrat]

Thanks for the explanations.

but did any of them help?

[elizabethr]

Thanks for the explanations.

but did any of them help?

Yes seems to add up..lol..Algebra was never my strong suit.